Question
Asked Dec 25, 2019
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The filament of a 75-W light bulb is at a temperature of 3300 K. Assuming the filament has an emissivity e = 1.0, find its surface area.

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Expert Answer

Step 1

Write the equation to calculate the power radiated by the bulb

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P = GA€T* o Stefan's- Boltzmann constant A→ Surface area of thefilament e → emissivity of thestar Temperature of thefilam ent T →

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Step 2

Rewrite the above expression i...

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oeT 75W (5.66696 ×10° w/m² -K* )(1.0)(3300K) =1.116 x10 m -2

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