Question
Asked Oct 13, 2019
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The first low of the thermodynamics shows U = Q - W, where U is a changing internal energy of the gas in the system, Q is a heat that the system received, and DW is work done by the system. If 15 kJ of heat flows out of a system and 30 kJ of work is done by the system, then what is the change in internal energy? 

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Expert Answer

Step 1

Given:

Heal flown out of the system = 15 kJ

Work done by the system = 30 kJ

Step 2

Calculating the change in t...

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According to first law of thermodynamics, U Q-W Where Qis the heat received by the system and W is the work done by the system Heat flown out of the system 15 kJ (Given) Then heat received by the system can be written, Q= -15 kJ W 30 kJ(Given) Hence, change in internal energy U (-15k)30KJ -45 kJ Change in internal energy, U - 45 kJ

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Thermodynamics

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