The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 103 s. Suppose we start with 0.0250 moles of N,Os(g) in a volume of 2.0L. a) How many moles of N2O5 will remain after 5.0 min? b) How many minutes will it take for the quantity of N2Os to drop to 0.010 moles? c) What is the half-life of N,Os at 70°C

Chemistry: Principles and Reactions
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Chapter11: Rate Of Reaction
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The first order rate constant for the decomposition of N205, according to the reaction:
2 N2O5(g)
->
4 NO2(g) + O2(g)
at 70°C is 6.82 x 103 s.
Suppose we start with 0.0250 moles of N,Os(g) in a volume of 2.0L.
a) How many moles of N2O5 will remain after 5.0 min?
b) How many minutes will it take for the quantity of N2Os to drop to 0.010 moles?
c) What is the half-life of N,Os at 70°C
Transcribed Image Text:The first order rate constant for the decomposition of N205, according to the reaction: 2 N2O5(g) -> 4 NO2(g) + O2(g) at 70°C is 6.82 x 103 s. Suppose we start with 0.0250 moles of N,Os(g) in a volume of 2.0L. a) How many moles of N2O5 will remain after 5.0 min? b) How many minutes will it take for the quantity of N2Os to drop to 0.010 moles? c) What is the half-life of N,Os at 70°C
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