The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 33 mol NaHCO3 and 77 mol HCl.HCl. moles of carbonic acid :  ____________________mol   Which of the two reactants limits the number of moles of H2 CO3 that can be made? 1. HCl 2. NaHCO3   How much excess reactant remains after the reaction? excess reactant : ___________________mol

Question

The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl).

Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 33 mol NaHCO3 and 77 mol HCl.HCl.

moles of carbonic acid :  ____________________mol
 
Which of the two reactants limits the number of moles of H2 CO3 that can be made?
1. HCl
2. NaHCO3
 
How much excess reactant remains after the reaction?
excess reactant : ___________________mol

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