The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl).Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 33 mol NaHCO3 and 77 mol HCl.HCl.moles of carbonic acid :  ____________________mol Which of the two reactants limits the number of moles of H2 CO3 that can be made?1. HCl2. NaHCO3 How much excess reactant remains after the reaction?excess reactant : ___________________mol

Question
Asked Sep 22, 2019

The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl).

Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 33 mol NaHCO3 and 77 mol HCl.HCl.

moles of carbonic acid :  ____________________mol
 
Which of the two reactants limits the number of moles of H2 CO3 that can be made?
1. HCl
2. NaHCO3
 
How much excess reactant remains after the reaction?
excess reactant : ___________________mol
check_circleExpert Solution
Step 1

Chemical reaction between NaHCO3 and HCl is given by:

NaHCO3HC -» H2CO3 NaCl
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NaHCO3HC -» H2CO3 NaCl

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Step 2

From the above balanced chemical reaction, it is clear that 1 mol of NaHCO3 reacts with 1 mole of HCl producing 1 mole of H2CO3 and 1 mole of NaCl.

Here, molar ratio between NaHCO3 and HCl is 1:1.

If we take 33 mol of NaHCO3 and 77 mol HCl, 33 mol of NaHCO3 react only with 33 moles of HCl and pro...

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