The following MINITAB output presents the results of a hypothesis test for a populationmean u. Some of the numbers are missing. Fill them in.One-Sample T: XTest of mu = 16 vs not = 16%3DVariableNMeanStDevSE Mean95% CIтРх11 13.2874(a)1.8389((b), (c)) (d) 0.171

From the given information, Thus, a) Standard deviation can be computed as: It is given that…

Answered: The following MINITAB output presents…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Each day for 200 days, a quality engineer samples 144 fuses rated at 15 A and measures the amperage at which they burn out. He performs a hypothesis test of H0 : μ = 15 versus H1 : μ ≠ 15, where μ is the mean burnout amperage of the fuses manufactured that day. a) On 10 of the 200 days, H0 is rejected at the 5% level. Does this provide conclusive evidence that the mean burnout amperage was different from 15 A on at least one of the 200 days? Explain. b) Would the answer to part (a) be different if H0 had been rejected on 20 of the 200 days? Explain.
The NAEP considers that a national average of 283 is an acceptable performance. Using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2019 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2019 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?
which of the following statements is true if when using null hypothesis testing, our p value (in the sig column of spss output) is 0.069? -reject the null hypothesis -daily to reject the null hypothesis -reject the alternative hypothesis -fail to reject the alternative hypothesis
In the past, the mean running time for a certain type of flashlight battery has been 9.6 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has decreased as a result. A hypothesis test is to be performed. Determine the null and alternative hypotheses. A. H0: µ ¥ 9.6 hours and H1: µ = 9.6 hours B. H0: µ = 9.6 hours and H1: µ ¥ 9.6 hours C. H0: µ = 9.6 hours and H1: µ > 9.6 hours D. H0: µ = 9.6 hours and H1: µ < 9.6 hours
If a researcher were conducting a two-tailed/non-directional hypothesis test with an alpha of 0.10 and a sample of size n=120, what would the Zcrit value be?
A hospital claims that the mean wait time for emergency room patients is more than 38 minutes. Identify the null hypothesis Ho, and the alternate hypothesis Ha in terms of the parameter
Also, using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2009 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2009 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?
A researcher is testing a two-tailed null hypothesis at the p < .01 level with df = 48. What critical value would she or he use? Justify your answer.
The National Institute of Mental Health published an article stating that in any one-year period, approximately 9.5 percent of American adults suffer from depression or a depressive illness. Suppose that in a survey of 100 people in a certain town, seven of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that town suffering from depression or a depressive illness is lower than the percent in the general adult American population. find the p value
A researcher is using a one-tailed hypothesis test with α = .01 to evaluate the effect of a treatment. If the critical/cut-off value is t = 2.479, how many individuals are in the sample
A researcher is concerned that his new antihypertensive medication may be causing insomnia in some of his patients. Suppose he gathers an SRS of 65 patients treated with the study drug with a sample average of 6.6 hours of sleep and a σ=1.1. Assuming that insomnia can be quantified as an average of 4.5 hours of sleep, can we determine with 95% confidence that his drug avoids diagnosis of insomnia as a side-effect?
If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT=+1.55?

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The following MINITAB output presents the results of a hypothesis test for a population mean u. Some of the numbers are missing. Fill them in. One-Sample T: X Test of mu = 16 vs not = 16 %3D Variable N Mean StDev SE Mean 95% CI тР х 11 13.2874 (a) 1.8389 ((b), (c)) (d) 0.171