The following sample observations were randomly selected. (Round intermediate calculations and final answers to 2 decimal places.) 4 y 7 Click here for the Excel Data File a. The regression equation is ŷ = b. When X is 8 this gives ŷ = 67 65

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y = – 17.88x + 41.39 and the r = - 0.405. What proportion of the variation in y can be explained by the variation in the values of x? r2 = Report answer as a percentage accurate to one decimal place.

The data show the chest size and weight of several bears. Find the regression​ equation, letting chest size be the independent​ (x) variable. Then find the best predicted weight of a bear with a chest size of 58 inches. Is the result close to the actual weight of 572 ​pounds? Use a significance level of 0.05.   Chest size​ (inches) 46 57 53 41 40 40   Weight​ (pounds) 384 580 542 358 306 320   LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression​ equation?   y=nothing+nothingx ​ (Round to one decimal place as​ needed.)

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported as y=−66.75x+57.0 and the r=−0.504. Report answer as a percentage accurate to one decimal place.

The datasetBody.xlsgives the percent of weight made up of body fat for 100 men as well as other variables such as Age, Weight (lb), Height (in), and circumference (cm) measurements for the Neck, Chest, Abdomen, Ankle, Biceps, and Wrist. We are interested in predicting body fat based on abdomen circumference. Find the equation of the regression line relating to body fat and abdomen circumference. Make a scatter-plot with a regression line. What body fat percent does the line predict for a person with an abdomen circumference of 110 cm? One of the men in the study had an abdomen circumference of 92.4 cm and a body fat of 22.5 percent. Find the residual that corresponds to this observation. Bodyfat Abdomen 32.3 115.6 22.5 92.4 22 86 12.3 85.2 20.5 95.6 22.6 100 28.7 103.1 21.3 89.6 29.9 110.3 21.3 100.5 29.9 100.5 20.4 98.9 16.9 90.3 14.7 83.3 10.8 73.7 26.7 94.9 11.3 86.7 18.1 87.5 8.8 82.8 11.8 83.3 11 83.6 14.9 87 31.9 108.5 17.3…

For each of the following data sets: plot the data, determine the regression equation, and add the graph of the regression to the graph.

We expect a car’s highway gas mileage to be related to its city gas mileage (in mpg). Data for all 1209 vehicles in the government’s 2016 Fuel Economy Guide give the regression line   highway mpg=7.903+(0.993×city mpg) for predicting highway mileage from city mileage. (a) What is the slope of this line? (Enter your answer rounded to three decimal places.) slope:     What does the numerical value of the slope tell you? For every 7.903 mpg in city gas mileage, highway gas mileage increases about 0.993 mpg. On average, highway mileage increases by 0.993 mpg for each additional mpg in city mileage. Highway gas mileage increases with city gas mileage by 7.903 mpg for each additional mpg in city mileage. On average, highway mileage decreases by 0.993 mpg for each additional mpg in city mileage. On average, highway mileage increases by 7.903 mpg for each additional mpg in city mileage. (b) What is the intercept? (Enter your answer rounded to three decimal…

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=20.41x+15.59y=20.41x+15.59and the r=0.272r=0.272.What proportion of the variation in y can be explained by the variation in the values of x?r² = %Report answer as a percentage accurate to one decimal place.

You generate a scatter plot using Excel. You then have Excel plot the trend line and report the equation and the r2r2 value. The regression equation is reported asy=60.71x+33.51y=60.71x+33.51and the r2=0.1764r2=0.1764.What is the correlation coefficient for this data set?r =

Using your favorite statistics software package, you generate a scatter plot with a regression equation and correlation coefficient. The regression equation is reported asy=−32.86x+33.54y=-32.86x+33.54and the r=−0.483r=-0.483.What proportion of the variation in y can be explained by the variation in the values of x?r² = %Report answer as a percentage accurate to one decimal place.