The following thermochemical equation is for the reaction of HCl(g) with NH3 (9) to form NH4Cl(s) HCl(g) + NH3(g) → NH₂Cl(s) AH = - 176 kJ How many grams of HCl(g) would have to react to produce 59.0 kJ of energy? grams
The following thermochemical equation is for the reaction of HCl(g) with NH3 (9) to form NH4Cl(s) HCl(g) + NH3(g) → NH₂Cl(s) AH = - 176 kJ How many grams of HCl(g) would have to react to produce 59.0 kJ of energy? grams
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.67QP: Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would...
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This is exothermic reaction as of the reaction is negative.
1 mole ammonia react with 1 mole hydrogen chloride and 176 KJ heat produced.
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