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Electrical EngineeringQ&A LibraryThe following three-phase loads are connected to a short transmission line with impedance per wire of 4 + j7 ohms: Load 1: Resistive load drawing 80 A, Load 2: Capacitor drawing 60 A, Load 3: Inductive load drawing 50 A at 80 % power factor. What is the sending end power factor for a receiving end voltage of 34.5 kV? a. 96 % b. 97 % c. 98 % d. 99 %Question

Asked Mar 12, 2020

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- The following three-phase loads are connected to a short transmission line with impedance per wire of 4 + j7 ohms: Load 1: Resistive load drawing 80 A, Load 2: Capacitor drawing 60 A, Load 3: Inductive load drawing 50 A at 80 % power factor. What is the sending end power factor for a receiving end voltage of 34.5 kV?

a. 96 % b. 97 % c. 98 % d. 99 %

Step 1

From the given load information calculate the total load current.

- The power dissipated by the resistive load will be purely active because the power factor is unity.
- There will be reactive power injected by the capacitor.
- Active and reactive power drawn by the inductive load.

Step 2

Calculate the total load current.

Step 3

For the short transmission line, the relation between the current is,

The sending end voltage is given by the following expression,

Substitute *Z* as the transmission line impedance.

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