The force exerted by the wind on the sails of a sailboat is F, = 495 N north. The water exerts a force of sail = 245 N east. If the boat (including its crew) has a mass of 325 kg, what are the magnitude and Fkeel direction of its acceleration?

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Chapter5: Newton's Law Of Motion
Section: Chapter Questions
Problem 93CP: If two tugboats pull on a disabled vessel, as shown here in an overhead view, the disabled vessel...
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Tutorial Exercise
The force exerted by the wind on the sails of a sailboat is F
= 495 N north. The water exerts a force of
sail
Fireel = 245 N east. If the boat (including its crew) has a mass of 325 kg, what are the magnitude and
direction of its acceleration?
Step 1
We choose east to be the positive x-direction and north to be the positive y-direction. The horizontal forces
acting on the 325 kg boat (including crew) are shown in the diagram.
|north
Fail
FR
east
keel
One method of finding the desired acceleration is to compute the resultant force F,: For the magnitude of the
R'
force, where
ΣF,-245
Ν and ΣF, -495
N,
we have
FR = V (EF,)? + (EF,)?
x x 105 N2) = 552
1.698
N.
Transcribed Image Text:Tutorial Exercise The force exerted by the wind on the sails of a sailboat is F = 495 N north. The water exerts a force of sail Fireel = 245 N east. If the boat (including its crew) has a mass of 325 kg, what are the magnitude and direction of its acceleration? Step 1 We choose east to be the positive x-direction and north to be the positive y-direction. The horizontal forces acting on the 325 kg boat (including crew) are shown in the diagram. |north Fail FR east keel One method of finding the desired acceleration is to compute the resultant force F,: For the magnitude of the R' force, where ΣF,-245 Ν and ΣF, -495 N, we have FR = V (EF,)? + (EF,)? x x 105 N2) = 552 1.698 N.
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