The free energy change for the following reaction at 25 °C, when [Ni2+] = 1.12 M and [Cd2+] = 1.96×10-3 M, is -45.3 kJ:Ni2+(1.12 M) + Cd(s)--------> Ni(s) + Cd2+(1.96×10-3 M) ΔG = -45.3 kJWhat is the cell potential for the reaction as written under these conditions?Answer: _______VWould this reaction be spontaneous in the forward or the reverse direction? ________
The free energy change for the following reaction at 25 °C, when [Ni2+] = 1.12 M and [Cd2+] = 1.96×10-3 M, is -45.3 kJ:Ni2+(1.12 M) + Cd(s)--------> Ni(s) + Cd2+(1.96×10-3 M) ΔG = -45.3 kJWhat is the cell potential for the reaction as written under these conditions?Answer: _______VWould this reaction be spontaneous in the forward or the reverse direction? ________
General Chemistry - Standalone book (MindTap Course List)
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ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter18: Thermodynamics And Equilibrium
Section: Chapter Questions
Problem 18.79QP: Is the following reaction spontaneous as written? Explain. Do whatever calculation is needed to...
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The free energy change for the following reaction at 25 °C, when [Ni2+] = 1.12 M and [Cd2+] = 1.96×10-3 M, is -45.3 kJ:
Ni2+(1.12 M) + Cd(s)--------> Ni(s) + Cd2+(1.96×10-3 M)
ΔG = -45.3 kJ
What is the cell potential for the reaction as written under these conditions?
Answer: _______V
Would this reaction be spontaneous in the forward or the reverse direction? ________
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