Question
Asked Apr 25, 2019
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The free energy change for the following reaction at 25 °C, when [Ni2+] = 1.12 M and [Cd2+] = 1.96×10-3 M, is -45.3 kJ:

Ni2+(1.12 M) + Cd(s)--------> Ni(s) + Cd2+(1.96×10-3 M)    

ΔG = -45.3 kJ

What is the cell potential for the reaction as written under these conditions?

Answer:  _______V

Would this reaction be spontaneous in the forward or the reverse direction? ________

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