11 QUESTION 11The function f(x) = 3 x4-4 x3-12 x2 +1, is increasing on the intervalOA (-0,-2)U(0,2)OB (-1,0) U (1, 0)O(-00,-1)U(0,2)OD (-1,0)U (2,x)

Name: 11 QUESTION 11The function f(x) = 3 x4-4 x3-12 x2 +1, is increasing on
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Description: 11 QUESTION 11The function f(x) = 3 x4-4 x3-12 x2 +1, is increasing on the intervalOA (-0,-2)U(0,2)OB (-1,0) U (1, 0)O(-00,-1)U(0,2)OD (-1,0)U (2,x)

f(x) = 3x4-4x3-12x2+1f'(x) = 12x3-12x2-24xf'(x) = 12x(x2-x-2)f'(x) = 12x(x2-2x+x-2)f'(x) =…

Answered: The function f(x) =3 x4-4 x3-12 x2+1,…

Math

Calculus

The function f(x) =3 x4-4 x3-12 x2+1, is increasing on the interval

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter3: Functions And Graphs

Section: Chapter Questions

Problem 52RE

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