The function given by y = f(x) shows the value of $5000 invested at 5% interest compounded continuously, x years after the money was originally invested. a. Find the average amount earned per year between the 5th year and 10th year. b. Find the average amount earned per year between the 20th year and the 25th year. c. Based on the answers from parts (a) and (b), does it appear that the rate at which annual income increases is increasing or decreasing with time? Value of $5000 with Continuous Compounding at 5% 24,000 у 3 f(х) 20,000 |(25, 17,452) 16,000 (20, 13,591)| 12,000 (10, 8244) 8,000 4,000 (5,6420) 5 10 15 20 25 30 Number of Years Value ($)

College Algebra
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Author:Jay Abramson
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Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
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The function given by y = f(x) shows the value of $5000 invested at 5% interest compounded continuously, x years after
the money was originally invested.
a. Find the average amount earned per year between the 5th year and 10th year.
b. Find the average amount earned per year between the 20th year and the 25th year.
c. Based on the answers from parts (a) and (b), does it appear that the rate at which annual income increases is increasing
or decreasing with time?
Value of $5000 with Continuous
Compounding at 5%
24,000
у 3 f(х)
20,000
|(25, 17,452)
16,000
(20, 13,591)|
12,000
(10, 8244)
8,000
4,000
(5,6420)
5 10 15 20 25 30
Number of Years
Value ($)
Transcribed Image Text:The function given by y = f(x) shows the value of $5000 invested at 5% interest compounded continuously, x years after the money was originally invested. a. Find the average amount earned per year between the 5th year and 10th year. b. Find the average amount earned per year between the 20th year and the 25th year. c. Based on the answers from parts (a) and (b), does it appear that the rate at which annual income increases is increasing or decreasing with time? Value of $5000 with Continuous Compounding at 5% 24,000 у 3 f(х) 20,000 |(25, 17,452) 16,000 (20, 13,591)| 12,000 (10, 8244) 8,000 4,000 (5,6420) 5 10 15 20 25 30 Number of Years Value ($)
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