The gas inside a cylinder expands against a constant external pressure of 0.991 atm from a volume of 3.65 L to a volume of 14.60 L. In doing so, it turns apaddle immersed in 0.908 L of liquid benzene (C6H6). Calculate the temperature rise of the liquid, assuming no loss of heat to the surroundings orfrictional losses in the mechanism. Take the density of liquid CgH, to be 0.879 g cm3 and its specific heat to be 1.74 J °C- g.Hints: The expansion work done by the gas is given by: w = -PexternalAV and 1 L atm =101.325 J.AT =°C

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Asked Mar 9, 2020
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The gas inside a cylinder expands against a constant external pressure of 0.991 atm from a volume of 3.65 L to a volume of 14.60 L. In doing so, it turns a
paddle immersed in 0.908 L of liquid benzene (C6H6). Calculate the temperature rise of the liquid, assuming no loss of heat to the surroundings or
frictional losses in the mechanism. Take the density of liquid CgH, to be 0.879 g cm3 and its specific heat to be 1.74 J °C- g.
Hints: The expansion work done by the gas is given by: w = -P
external
AV and 1 L atm =
101.325 J.
AT =
°C
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The gas inside a cylinder expands against a constant external pressure of 0.991 atm from a volume of 3.65 L to a volume of 14.60 L. In doing so, it turns a paddle immersed in 0.908 L of liquid benzene (C6H6). Calculate the temperature rise of the liquid, assuming no loss of heat to the surroundings or frictional losses in the mechanism. Take the density of liquid CgH, to be 0.879 g cm3 and its specific heat to be 1.74 J °C- g. Hints: The expansion work done by the gas is given by: w = -P external AV and 1 L atm = 101.325 J. AT = °C

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Since, there is no heat loss. Hence all the work don...

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