# The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean pricepaid is \$2000 and the standard deviation is \$801760 1840 1920 2000 2080 2160 2240Distribution of PricesWhat is the approximate percentage of buyers who paid between \$2000 and S2160?9%What is the approximate percentage of buyers who paid between \$1920 and \$2080?00What is the approximate percentage of buyers who paid between \$2000 and S2080?00What is the approximate percentage of buyers who paid more than \$21600What is the approximate percentage of buyers who paid berween \$2000 and \$2240?0What is the approximate percentage of buyers m ho paid less than \$1760?

Question help_outlineImage TranscriptioncloseThe graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is \$2000 and the standard deviation is \$80 1760 1840 1920 2000 2080 2160 2240 Distribution of Prices What is the approximate percentage of buyers who paid between \$2000 and S2160? 9% What is the approximate percentage of buyers who paid between \$1920 and \$2080? 0 0 What is the approximate percentage of buyers who paid between \$2000 and S2080? 0 0 What is the approximate percentage of buyers who paid more than \$2160 0 What is the approximate percentage of buyers who paid berween \$2000 and \$2240? 0 What is the approximate percentage of buyers m ho paid less than \$1760? fullscreen
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Step 1

Given Information :

Mean (µ) = \$2000

Standard Deviation  = \$80

Let X be the random variable denoting the price of HD television.

a)  The approximate percentage of buyers who paid between \$2000 and \$2160 can be calculates as shown ;

Step 2

b)  The approximate percentage of buyers who paid between \$1920 and \$2080 can be calculates as shown ;

Step 3

c)  The approximate percentage of buyers who paid between \$...

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