Question
Asked Dec 7, 2019
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The heat of formation of Fe2O3(s) is 826.0 kJ/mol. Calculate the heat of the reaction when a 43.20 g sample of iron is reacted.
 
a. 159.7 kJ
b. 1.784 × 104 kJ
c. 638.9 kJ
d. 1278 kJ
e. 319.5 kJ
 
thanks for your help! :)
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Expert Answer

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Step 1

Given,

Heat of formation of Fe2O3 = 826.0 kJ/mol

Mass of iron, Fe = 43.20 g

Moles of Fe can be calculated as:

 

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Mass 43.20 g Moles of Fe 0.7742 mol Molar mass 55.8 g/mol

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Step 2

The balanced chemical reaction for the formation of Fe2O3 from iron, Fe can be written as :

4 Fe (s) + 3 O2 (g) → 2 Fe2O3 (s)

From the given reaction, it is evident that : 

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4 mol Fe produces 2 mol Fe2O3 2 mol Fe203 .. 0.7742 mol Fe produces x 0.7742 mol of Fe 4 mol Fe = 0.3871 mol Fe2O3

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Step 3

The standard enthalpies of formation are:

△f H (Fe) = 0 kJ/mol

△f H (O2) = 0 kJ/mol

△f H (Fe2O3) = 826.0 kJ/mol

The hea...

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ΔΗΣ Δ:Η (products) -Σ ΔrΗ (reactants) ΔΗΚ- [ΔtΗ (Fe2O:)]-[AΗ (Fe) + ΔιΗ (Ο2)] ΔΗΚ[0.3871 mol x 826.0 kJmol] -[ 0+0 ] ΔΗΚ- 319.74 kJ

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