The height above ground of an object moving vertically is given by s = -16t2 + 96t + 112, with s in feet and t in seconds. Find a. the object’s velocity when t = 0; b. its maximum height and when it occurs; c. its velocity when s =0.

The height above ground of an object moving vertically is given by s = -16t2 + 96t + 112, with s in feet and t in seconds. Find a. the object’s velocity when t = 0; b. its maximum height and when it occurs; c. its velocity when s =0.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section: Chapter Questions

Problem 6T

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Question

The height above ground of an object moving vertically is given by s = -16t2 + 96t + 112, with s in feet and t in seconds. Find

a. the object’s velocity when t = 0;

b. its maximum height and when it occurs;

c. its velocity when s =0.

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