The highest mountain on Mars is Olympus Mons, rising 22 000 meters above the Martian surface. If we were to throw an object horizontally off the mountain top, how long would it take to reach the surface? (Ignore atmospheric drag forces and use g Mars = 3.72 m/s 2.) a.2.4 minutes b.0.79 minute c.1.8 minutes d.3.0 minutes

Question
Asked Oct 10, 2019

The highest mountain on Mars is Olympus Mons, rising 22 000 meters above the Martian surface. If we were to throw an object horizontally off the mountain top, how long would it take to reach the surface? (Ignore atmospheric drag forces and use g Mars = 3.72 m/s 2.)

a.
2.4 minutes

b.
0.79 minute

c.
1.8 minutes

d.
3.0 minutes

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Expert Answer

Step 1

The equation of motion is given by

1
h ut-at
2
Here, h is the distance travelled, u is the initial speed, t is the time taken for the motion and a is the
acceleration
Take the downward direction to be positive. Since the object is horizontally, its initial vertical speed
will be zero. The acceleration in vertical direction will be equal to the acceleration due to gravity
Substitute 0 for u and g for a in the above equation
1
h= 0+gt
2
2
1
gt2
2h
2h
t =
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1 h ut-at 2 Here, h is the distance travelled, u is the initial speed, t is the time taken for the motion and a is the acceleration Take the downward direction to be positive. Since the object is horizontally, its initial vertical speed will be zero. The acceleration in vertical direction will be equal to the acceleration due to gravity Substitute 0 for u and g for a in the above equation 1 h= 0+gt 2 2 1 gt2 2h 2h t =

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Step 2

Substitute the numerical values...

2(22000 m
t =
3.72 m/s
108.76 s
108.76 smin
60 s
1.8 min
help_outline

Image Transcriptionclose

2(22000 m t = 3.72 m/s 108.76 s 108.76 smin 60 s 1.8 min

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Newtons Laws of Motion

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