the horizontal as shown in the diagram below. A bullet of mass 0.02 kg is fired into the block with a velocity of 20 m.s' and becomes embedded in it. The coefficient of friction between the block and the surface is 0.2. 20 m/s 0,5 kg 30° 0,02 kg (a) Draw a fully labeled diagram showing all forces on the bullet-block system. (b) Use: (i) the conservation of momentum to determine the velocity of the bullet and the block system after impact. [3] (ii) Newton's second law of motion to determine the frictional force. [5] (iii) the conservation of total energy to find the distance moved by the bullet-block system up the plane. [4 [2]

Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter9: Dynamics Of A System Of Particles
Section: Chapter Questions
Problem 9.60P
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2. A 0.5 kg wooden block rests at the bottom of an inclined plane, which makes an angle of 30° with
the horizontal as shown in the diagram below. A bullet of mass 0.02 kg is fired into the block
with a velocity of 20 m.s and becomes embedded in it. The coefficient of friction between the
block and the surface is 0.2.
20 m/s
0,5 kg
30°
0,02 kg
(a) Draw a fully labeled diagram showing all forces on the bullet-block system.
(b) Use:
(i) the conservation of momentum to determine the velocity of the bullet and the block
system after impact.
[3]
(ii) Newton's second law of motion to determine the frictional force.
[5]
(iii) the conservation of total energy to find the distance moved by the bullet-block system
up the plane.
[4
[2]
Transcribed Image Text:2. A 0.5 kg wooden block rests at the bottom of an inclined plane, which makes an angle of 30° with the horizontal as shown in the diagram below. A bullet of mass 0.02 kg is fired into the block with a velocity of 20 m.s and becomes embedded in it. The coefficient of friction between the block and the surface is 0.2. 20 m/s 0,5 kg 30° 0,02 kg (a) Draw a fully labeled diagram showing all forces on the bullet-block system. (b) Use: (i) the conservation of momentum to determine the velocity of the bullet and the block system after impact. [3] (ii) Newton's second law of motion to determine the frictional force. [5] (iii) the conservation of total energy to find the distance moved by the bullet-block system up the plane. [4 [2]
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