The illumination provided by a car's headlight varies inversely as the square of the distance from the headlight. A car's headlight produces an illumination of 3.75 footcandles at a distance of 40 feet. What is the illumination when the distance is 50 feet?
Let, illumination be “I” and distance of illumination from headlight be “D”.
Therefore, I ∝ 1/(D^2).
Whenever the proportionality sign is changed to an equality sign, a constant “k” is multiplied on the right side of the equation.
Now, substituting the values of I at 40 feet and 50 feet and obtaining two equations....
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