The illustration shows how a geometric wall hanging can be created by stretching yarn from peg to peg across a wooden ring. The relationship between the number of pegsp placed evenly around the ring and the number of yarn segments s that crisscross the ring is given by the formula s = PlP - 3) 2. How many pegs are needed if the designer wants 35 segments to crisscross the ring? (Hint: Multiply both sides of the equation by 2.) See Example 1. p = pegs

The illustration shows how a geometric wall hanging can be created by stretching yarn from peg to peg across a wooden ring. The relationship between the number of pegsp placed evenly around the ring and the number of yarn segments s that crisscross the ring is given by the formula s = PlP - 3) 2. How many pegs are needed if the designer wants 35 segments to crisscross the ring? (Hint: Multiply both sides of the equation by 2.) See Example 1. p = pegs

Intermediate Algebra

19th Edition

ISBN:9780998625720

Author:Lynn Marecek

Publisher:Lynn Marecek

Chapter2: Solving Linear Equations

Section2.3: Solve A Formula For A Specific Variable

Problem 241E: Look at the two figures below. (a) Which figure looks like it has the larger area? Which looks like...

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