The ionic compound, CsI, forms a body centered cubic structure (see below) where the anions occupy the corners of the crystal (red) and the cations the body centered position (green). If the density of the compound is 4.51 g/cm^3 and the ionic radius of Cs + is 169 pm, what is the ionic radius of I − in pm? Key Concept: The atoms are touching the diagonal in the center of the cube. This makes it equal to the sum of 2 times the radius of each atom.
The ionic compound, CsI, forms a body centered cubic structure (see below) where the anions occupy the corners of the crystal (red) and the cations the body centered position (green). If the density of the compound is 4.51 g/cm^3 and the ionic radius of Cs + is 169 pm, what is the ionic radius of I − in pm?
Key Concept: The atoms are touching the diagonal in the center of the cube. This makes it equal to the sum of 2 times the radius of each atom.
Strategy: Determine the length of the diagonal,d, and recall that the length of the side, l, is given by l = d/3 0.5. This is a result of the use of the Pythagorean theorem relating the length of the side to d.
With the length of the side you can determine the volume of the unit cell.
From the number of atoms in the unit cell determine the mass of the unit cell.
Use these to get the density.
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