The lattice energy of potassium iodide is the energy required for the following reaction. KI(s) → K+(g) + I−(g)  ΔHrxn = ΔHlattice Use the Born-Haber cycle to calculate  ΔHlattice for KI(s) from the information given below. Equation 1: 2 K(s) + I2(g) → 2 KI(s)      ΔH1 = −655 kJ/mol Equation 2: K(s) → K(g)      ΔH2 = 89 kJ/mol Equation 3: I2(g) → 2 I(g)      ΔH3 = 214 kJ/mol Equation 4: K(g) → K+(g) + e−      ΔH4 = 419 kJ/mol Equation 5: I(g) + e− → I−(g)      ΔH5 = −294 kJ/mol

Chemistry: The Molecular Science
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Chapter19: The Chemistry Of The Main-group Elements
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The lattice energy of potassium iodide is the energy required for the following reaction. KI(s) → K+(g) + I(g)  ΔHrxn = ΔHlattice

Use the Born-Haber cycle to calculate  ΔHlattice for KI(s) from the information given below.

Equation 1: 2 K(s) + I2(g) → 2 KI(s)      ΔH1 = −655 kJ/mol
Equation 2: K(s) → K(g)      ΔH2 = 89 kJ/mol
Equation 3: I2(g) → 2 I(g)      ΔH3 = 214 kJ/mol
Equation 4: K(g) → K+(g) + e      ΔH4 = 419 kJ/mol
Equation 5: I(g) + e → I(g)      ΔH5 = −294 kJ/mol
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