The lens - maker’s equation for a lens with index n1 immersedin a medium with index n2 takes the form 1/f =(n1 / n2 -1) (1/R1 -1/R2)   A thin diverging glass (index = 1.50) lens with R1 = -3.00 mand R2 = -6.00 m is surrounded by air. An arrow is placed10.0 m to the left of the lens. (a) Determine the position ofthe image. Repeat part (a) with the arrow and lens immersedin (b) water (index 5 1.33) and (c) a medium with an indexof refraction of 2.00. (d) How can a lens that is diverging inair be changed into a converging lens?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
Problem 40P
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The lens - maker’s equation for a lens with index n1 immersed
in a medium with index n2 takes the form

1/f =(n1 / n-1) (1/R1 -1/R2)

 

A thin diverging glass (index = 1.50) lens with R1 = -3.00 m
and R2 = -6.00 m is surrounded by air. An arrow is placed
10.0 m to the left of the lens. (a) Determine the position of
the image. Repeat part (a) with the arrow and lens immersed
in (b) water (index 5 1.33) and (c) a medium with an index
of refraction of 2.00. (d) How can a lens that is diverging in
air be changed into a converging lens?

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