The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received is 87.3 seconds. A manager devises a new drive-through system that he believes will decrease wait time. As a test, he initiates the new system at his restaurant and measures the wait time for 10 randomly selected orders. The wait times are provided in the table to the right. Complete parts (a) and (b) below. 103.3 81.3 69.8 95.4 59.9 85.9 73.8 72.2 67.1 81.3 Click the icon to view the table of correlation coefficient critical values. (a) Because the sample size is small, the manager must verify that the wait time is normally distributed and the sample does not contain any outliers. The normal probability plot is shown below and the sample correlation coefficient is known to be e=0.983 Are the conditions for testing the hypothesis satisfied? ▼ No, Yes, the conditions ▼ are are not satisfied. The normal probability plot ▼ is is not linear enough, since the correlation coefficient is ▼ greater less than the critical value. (b) Is the new system effective? Conduct a hypothesis test using the P-value approach and a level of significance of alpha equals 0.01α=0.01. First determine the appropriate hypotheses. Upper H 0H0: ▼ muμ sigmaσ pp ▼ less than< not equals≠ greater than> equals= 87.3 Upper H 1H1: ▼ sigmaσ muμ pp ▼ greater than> not equals≠ equals= less than< 87.3 Find the test statistic. t 0t0equals=nothing (Round to two decimal places as needed.) Find the P-value. The P-value is nothing. (Round to three decimal places as needed.) Use the alpha equals α=0.01 level of significance. What can be concluded from the hypothesis test? A. The P-value is greatergreater than the level of significance so there isnbsp sufficient evidence to conclude the new system is effective. B. The P-value is greatergreater than the level of significance so there isnbsp not nbsp not sufficient evidence to conclude the new system is effective. C. The P-value is lessless than the level of significance so there isnbsp not nbsp not sufficient evidence to conclude the new system is effective. D. The P-value is lessless than the level of significance so there isnbsp sufficient evidence to conclude the new system is effective.

The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received is 87.3 seconds. A manager devises a new drive-through system that he believes will decrease wait time. As a test, he initiates the new system at his restaurant and measures the wait time for 10 randomly selected orders. The wait times are provided in the table to the right. Complete parts (a) and (b) below. 103.3 81.3 69.8 95.4 59.9 85.9 73.8 72.2 67.1 81.3 Click the icon to view the table of correlation coefficient critical values. (a) Because the sample size is small, the manager must verify that the wait time is normally distributed and the sample does not contain any outliers. The normal probability plot is shown below and the sample correlation coefficient is known to be e=0.983 Are the conditions for testing the hypothesis satisfied? ▼ No, Yes, the conditions ▼ are are not satisfied. The normal probability plot ▼ is is not linear enough, since the correlation coefficient is ▼ greater less than the critical value. (b) Is the new system effective? Conduct a hypothesis test using the P-value approach and a level of significance of alpha equals 0.01α=0.01. First determine the appropriate hypotheses. Upper H 0H0: ▼ muμ sigmaσ pp ▼ less than< not equals≠ greater than> equals= 87.3 Upper H 1H1: ▼ sigmaσ muμ pp ▼ greater than> not equals≠ equals= less than< 87.3 Find the test statistic. t 0t0equals=nothing (Round to two decimal places as needed.) Find the P-value. The P-value is nothing. (Round to three decimal places as needed.) Use the alpha equals α=0.01 level of significance. What can be concluded from the hypothesis test? A. The P-value is greatergreater than the level of significance so there isnbsp sufficient evidence to conclude the new system is effective. B. The P-value is greatergreater than the level of significance so there isnbsp not nbsp not sufficient evidence to conclude the new system is effective. C. The P-value is lessless than the level of significance so there isnbsp not nbsp not sufficient evidence to conclude the new system is effective. D. The P-value is lessless than the level of significance so there isnbsp sufficient evidence to conclude the new system is effective.

Elements Of Modern Algebra

8th Edition

ISBN:9781285463230

Author:Gilbert, Linda, Jimmie

Publisher:Gilbert, Linda, Jimmie

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The mean waiting time at the drive-through of a fast-food restaurant from the time an order is placed to the time the order is received is 87.3 seconds. A manager devises a new drive-through system that he believes will decrease wait time. As a test, he initiates the new system at his restaurant and measures the wait time for 10 randomly selected orders. The wait times are provided in the table to the right. Complete parts (a) and (b) below.	103.3	81.3
69.8	95.4
59.9	85.9
73.8	72.2
67.1	81.3

Click the icon to view the table of correlation coefficient critical values.

(a) Because the sample size is small, the manager must verify that the wait time is normally distributed and the sample does not contain any outliers. The normal probability plot is shown below and the sample correlation coefficient is known to be

e=0.983

Are the conditions for testing the hypothesis satisfied?

▼

No,

Yes,

the conditions

▼

are

are not

satisfied. The normal probability plot

▼

is not

linear enough, since the correlation coefficient is

▼

greater

less

than the critical value.

(b) Is the new system effective? Conduct a hypothesis test using the P-value approach and a level of significance of

alpha equals 0.01α=0.01.

First determine the appropriate hypotheses.

Upper H 0H0:

▼

muμ

sigmaσ

▼

less than<

not equals≠

greater than>

equals=

87.3

Upper H 1H1:

▼

sigmaσ

muμ

▼

greater than>

not equals≠

equals=

less than<

87.3

Find the test statistic.

t 0t0equals=nothing

(Round to two decimal places as needed.)

Find the P-value.

The P-value is

nothing.

(Round to three decimal places as needed.)

Use the

alpha equals α=0.01

level of significance. What can be concluded from the hypothesis test?

The P-value is

greatergreater

than the level of significance so there

isnbsp sufficient

evidence to conclude the new system is effective.

The P-value is

greatergreater

than the level of significance so there

isnbsp not nbsp not sufficient

evidence to conclude the new system is effective.

The P-value is

lessless

than the level of significance so there

isnbsp not nbsp not sufficient

evidence to conclude the new system is effective.

The P-value is

lessless

than the level of significance so there

isnbsp sufficient

evidence to conclude the new system is effective.

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