Asked Nov 23, 2019

The molar mass of Al2(CO3)is 243.88 g/mol.How many atoms of oxygen are contained in 43.5 g of Al2(CO3)3?


Expert Answer

Step 1

The number of moles of Al2(CO3)3 present in the given sample is calculated using equation (1). In this equation, n represents the number of moles, m represents the mass, and M represents the molar mass of the species.

43.5 g
243.88 g/mol
0.178 mol

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.(1) 43.5 g A(CO) 243.88 g/mol 0.178 mol

Step 2

Each Al2(CO3)3 molecule consists of 9 oxygen atoms. Therefore, the number of moles of oxygen atoms present in the given sample will be 9 times to the moles of Al2(CO3)3.

=9x0.178 mol
=1.602 mol

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=9x0.178 mol atoms =1.602 mol

Step 3

One mole of a substance contains 6.022 × 1023 atoms which is known as Avogadro number. From...

6.022x105 atoms
Number of O atoms = 1.602 molx-
1.0 mol
=9.65 x 10

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6.022x105 atoms Number of O atoms = 1.602 molx- 1.0 mol 23 =9.65 x 10 atoms


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