Question
Asked Sep 1, 2019
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the new jersey barrier is commonly used during highway construction. determine its weight per foot of length if it is made from plain stone concrete

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Expert Answer

Step 1

We have to find out the weight per foot of length of the new jersey barrier which is commonly used during highway construction.

Following is the figure of new jersey barrier with dimensions:  

4 inches
12 inches
750
.
550
6 inches
24 inches
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4 inches 12 inches 750 . 550 6 inches 24 inches

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Step 2

we know that the density of plain stone concrete is = 144 lb/ft3

The section of the barrier is divided into three parts:

Consider following as the first section:

6 inch
24 inches
Area of the first section = L x B
= 24inch x6inch
= 144.00in2
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6 inch 24 inches Area of the first section = L x B = 24inch x6inch = 144.00in2

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Step 3

Second section is ...

X inches
12 inches
550
24 inches
inches
Yinches
Area of the second section
2[Area of triangle] Area of rectangle
We have from the figure
12
Tan 55
Y
12
inch 8.402inch
Y =
Tan 55
Area of tri angle = 12inchx Yinch
= 12inchx 8.402 inch
=100.83 inch2.
Area of rectangle = 12 inch xX inch
Area of rectangle 12 inch x24-2(8.402)]inch
= 12inch x[24 16.804]inch
= 12inch x 7.196inch
86.352 inch2
Substitute the values, we have
Area of the second section 2[Area of tri angle] Area of rectangle
= 2[100.83 inch2 +86.352 inch2
201.66inch286.352inch2
=
288.012 inch2
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X inches 12 inches 550 24 inches inches Yinches Area of the second section 2[Area of triangle] Area of rectangle We have from the figure 12 Tan 55 Y 12 inch 8.402inch Y = Tan 55 Area of tri angle = 12inchx Yinch = 12inchx 8.402 inch =100.83 inch2. Area of rectangle = 12 inch xX inch Area of rectangle 12 inch x24-2(8.402)]inch = 12inch x[24 16.804]inch = 12inch x 7.196inch 86.352 inch2 Substitute the values, we have Area of the second section 2[Area of tri angle] Area of rectangle = 2[100.83 inch2 +86.352 inch2 201.66inch286.352inch2 = 288.012 inch2

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