Does coordination of NO as a ligand to an electron-rich transition metal cause the N—O bond length to increase or decrease? Justify your answer.
Does coordination of NO as a ligand to an electron-rich transition metal cause the N—O bond length to increase or decrease? Justify your answer.
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Isn't An electron-rich transition metal has a low oxidation state, meaning that the metal centre has gained electrons from the nitrogen on NO when it coordinates as a ligand? Therefore, N-O bond length decases.
by Bartleby Expert"The NO molecule has an unpaired electron in it π* orbital which will be donate to an electron-rich transition metal’s partially filled d-orbital, resulting in a partially covalent metal-ligand bond. This interaction causes the number of antibonding electrons in the N-O bond decreases. As a results, the bond order increase. The bond length is inversely proportional to the bond order, therefore transfer of electrons from NO ligand to metal leads to a decrease in bond length."
Is my understanding correct?
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