The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?
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The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?
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- For the calculation of sd, shouldn't it be (0.97-1.09) and so on... because 0.97 = x and 1.09 = mean? and the formula for sd is squared of the summation of (x-mean)^2 divide by n?For the standard equation, shouldn't it be (0.97-1.09) and so on... because (x-mean)Sum of coefficients C7H8 + O2 --> CO2 + H2O after balancing
- V26A pipet is used to transfer 3.00 mL of a 2.00 M stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask “S” to a 25.00-mL volumetric flask “B,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
- Chemistry In an analysis of the content of carbohydrate present in a glycoprotein, the following results were found: 12.6, 11.9, 13.0, 12.7 and 12.5 g of carbohydrate per 100 g of protein. Taking into account that σ is unknown, the confidence interval for the average value at a 90% confidence level of the carbohydrate content is: Select one:to. 12.5 ± 0.4b. 12.5 ± 0.2c. 12.5 ± 0.5d. 12.5 ± 0.3Is it necessary to know [E]T to determine (a) KM, (b) Vmax, or (c) kcat?A core sample is saturated with an oil (?o = 35oAPI), gas and water. The initial weight of the sample is 224.14 g. After the gas is displaced by water (?w = 1 g/cm3 ), the weight is increased to 225.90 g. The sample is the placed in a Soxhlet distillation apparatus, and 4.4 cm3 water is extracted. After drying the core sample, the weight is now 209.75 g. The sample bulk volume, 95 cm3 is measured in a mercury pycnometer. Find the porosity, water saturation, oil saturation, gas saturation and lithology of the core sample.
- Given the following data forMass of test tube, beaker and cyclohexane = 100.17 gMass of test tube and beaker = 84.07 gFreezing point of cyclohexane = 6.59 oCMass of weighing paper + naphthalene =1.080 gMass of weighing paper = 0.928 gFreezing point solution = 5.11oCKf = 20.8oC/mDetermine the followinga. mass of cyclohexane in g (2 decimal places); _____b. mass of naphthalene in g (4 decimal places); _____c. freezing point depression (2 decimal places); _____d. molality of solution (3 significant figures); _____e. moles of naphthalene (3 significant figures); _____f. molar mass of naphthalene, experimentally (3 significant figures); _____g. % error if theoretical molar mass of naphthalene is 128.17 g/ mole, USE ABSOLUTE VALUE (3 significant figure); ____The combustion of ammonia in the presence of excess oxygen yields NO2 and H2O: 4 NH3 (g) + 7 O2 (g) → 4 NO2 (g) + 6 H2O (g) The combustion of 153 g of ammonia consumes __________ g of oxygen. Atomic weights: N=14.01, H=1.01, O=15.99. Input values only with 2 decimal places.When concentrated nitric is sold, the label contains no mention of the molarity of the acid. Instead, the label normally lists the concentration of nitric acid as a wt/wt percent and gives the specific gravity of the solution. If the solution is 68.0 (wt/wt %) and nitric acid and has a specific gravity of 1.41 kg/L, calculate the molarity of 68.0 % concentrated nitric acid. FW HNO3=63.01g/mol