The polynomial f(x) = x - ix? + 2ix + 2 has the com- plex number i as a zero; however, the conjugate -i of i is not a zero. Why doesn't this result contradict the theorem on conjugate pair zeros of a polynomial?

Q: correct answer for all parts

A: Zeros of the polynomial

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A: Find the zeros of the polynomials f(x) =x2 -5x2 -16x +80 ,if it's two zeros are equal in magnitude…

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A: conjugate of x will also be a zero of polynominal

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A: topic - intermediate value theorem

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A: Show that the polynomial does not have any rational zeros. P(x) = x3 - x - 2

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A: Explained below

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A: Answer is in below steps.

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A: a. Consider the given polynomial: Since So, complex number i is one zero of . But

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A: *to find:- roots of the given equation.

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A: (19). According to question, given function, fx = 3x3 -17 x2 +27

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A: The given polynomial is  P(x) = x4 +x3 + 7x2 + 9x - 18

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A: Given: f(x)=x2+2ix-10

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A: Let's find.

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A:

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A: Given that, fx=3x3-10x+9

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