Question

Asked Feb 13, 2019

The position

r

→

of a particle moving in an xy plane is given by

r

→

=

(

5.00

t

3

−

6.00

t

)

i

^

+

(

2.00

−

2.00

t

4

)

j

^

with

r

→

in meters and t in seconds. In unit-vector notation, calculate

(a)

r

→

, (b)

v

→

, and (c)

a

→

for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the range of (-180o; 180o).

Step 1

Given

time, t= 2.00 sec and

the position vector as,

Step 2

a) Postion vector r at t=2.00 sec

Step 3

b) Velocity is the rate of change of positio...

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