The positionr→of a particle moving in an xy plane is given byr→=(5.00t3−6.00t)i^+(2.00−2.00t4)j^withr→in meters and t in seconds. In unit-vector notation, calculate(a)r→, (b)v→, and (c)a→for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the range of (-180o; 180o).

Question
Asked Feb 13, 2019

The position
r

of a particle moving in an xy plane is given by
r

=
(
5.00
t
3

6.00
t
)
i
^
+
(
2.00

2.00
t
4
)
j
^
with
r

in meters and t in seconds. In unit-vector notation, calculate
(a)
r

, (b)
v

, and (c)
a

for t = 2.00 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 2.00 s? Give your answer in the range of (-180o; 180o).

check_circleExpert Solution
Step 1

Given

time, t= 2.00 sec and

the position vector as,

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Step 2

a) Postion vector r at t=2.00 sec

 

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Step 3

b) Velocity is the rate of change of positio...

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