The positive and negative plates of a parallel-plate capacitor have an area of 3.05 cm by 3.05 cm. Their surface charge densities are +1.00×10-6 C/m2 and -1.00×10-6 C/m2, respectively. A proton moving parallel to the plates enters the middle of the space between them at a speed of 7.70×106 m/s. Assuming the field outside the capacitor is 0 and the field inside is uniform, how far to the side will the proton's path have deviated when it gets to the far end of the capacitor?

Question

The positive and negative plates of a parallel-plate capacitor have an area of 3.05 cm by 3.05 cm. Their surface charge densities are +1.00×10-6 C/m2 and -1.00×10-6 C/m2, respectively. A proton moving parallel to the plates enters the middle of the space between them at a speed of 7.70×106 m/s. Assuming the field outside the capacitor is 0 and the field inside is uniform, how far to the side will the proton's path have deviated when it gets to the far end of the capacitor?

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