
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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(a) Use a calculator with
x = | |
s = |
(b) Find a 90% confidence interval for the P/E population mean μ of all large U.S. companies. (Round your answers to one decimal place.)
lower limit | |
upper limit |
(c) Find a 99% confidence interval for the P/E population mean μ of all large U.S. companies. (Round your answers to one decimal place.)
lower limit | |
upper limit |

Transcribed Image Text:The price of a share of stock divided by the company's estimated future earnings per share is called the P/E ratio. High P/E ratios usually indicate "growth" stocks, or maybe
stocks that are simply overpriced. Low P/E ratios indicate "value" stocks or bargain stocks. A random sample of 51 of the largest companies in the United States gave the
following P/E ratiost.
11
35
19
13
15
21
40
18
60
72
9.
20
29
53
16
26
21
14
21
27
10
12
47
14
33
14
18
17
20
19
13
25
23
27
16
8.
49
44
20
27
8.
19
12
31
67
51
26
19
18
32
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- In a survey, 23 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $47 and standard deviation of $9. Construct a confidence interval at a 80% confidence level.Give your answers to one decimal place.________ ± ________Interpret your confidence interval in the context of this problem.arrow_forwardTina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.arrow_forward1. A recent study of 22 motorists showed that they spent an average of P750 per week. The standard deviation of the sample was P90. Find the 99% confidence interval of the true mean. Solution: 2. A sample of 15 National Collegiate Athletics Association (NCAA) basketball players had an average height of 6 feet with a sample standard deviation of 0.80 foot. Find the 90% confidence interval of the true mean height of all players. Solution:arrow_forward
- You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 44 business days, the mean closing price of a certain stock was $124.01. Assume the population standard deviation is $964. The 90% confidence interval is ( (Round to two decimal places as needed.) (1,1) More Clear all Final che View an example Get more help - Help me solve this MacBook Air DII SO F4 F3 %23 8 3 4 5 6 2 Q E R Y W E G H K トarrow_forwardIf X=115, σ=22, and n=36, construct a 95% confidence interval estimate of the population mean, μ. Click here to view page 1 of the cumulative standardised normal distribution table. LOADING... Click here to view page 2 of the cumulative standardised normal distribution table. LOADING... The 95% confidence interval is enter your response here≤μ≤enter your response here. (Round to two decimal places as needed.)arrow_forwardA market surveyor wishes to know how many energy drinks teenagers drink each week. They want to construct a 80% confidence interval with an error of no more than 0.07 . A consultant has informed them that a previous study found the mean to be 3.6 energy drinks per week and found the variance to be 1.44 . What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.arrow_forward
- You would like to construct a 99% confidence interval to estimate today's population mean temperature, so you make a series of measurements (a random sample) throughout the day. The mean of these measurements is 58.5 degrees Fahrenheit, and their standard deviation is 3.0 degrees Fahrenheit. For each of the following sampling scenarios, determine which distribution should be used to calculate the critical value for the 99% confidence interval for the population mean.(In the table, Z refers to a standard normal distribution, and t refers to a t distribution.)arrow_forwardIf n=19, ¯x(x-bar)=34, and s=12, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place. ________________< μ <_____________________arrow_forwardIn a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $44 and standard deviation of $6. Construct a confidence interval at a 98% confidence level.Give your answers to one decimal place._______________ ± _______________Interpret your confidence interval in the context of this problem.arrow_forward
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