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Social ScienceThe probability that a person in the United States has Type B+ blood is 8%. Four unrelated people in the United States are selected at random. Complete parts (a) through (d).(a) Find the probability that all four have type B+ blood.(b) Find the probability none have B+ blood.(c) Find the probability that one of the four have B+ blood.(d) Which of the events can be considered unusual? Explain.
The probability that a person in the United States has Type B+ blood is 8%. Four unrelated people in the United States are selected at random. Complete parts (a) through (d).
(a) Find the probability that all four have type B+ blood.
(b) Find the probability none have B+ blood.
(c) Find the probability that one of the four have B+ blood.
(d) Which of the events can be considered unusual? Explain.
Expert Answer
Solution: We are given that the probability that a person in the United States has Type B+ blood = 0.08. Also we are told that four unrelated people in the United States are selected at random.
(a) We have to find here the probability that all four have type B+ blood.
Since the events are independent, therefore, we have:
Probability that all four have B+ blood = 0.08 x 0.08x 0.08x0.08
= 0.000041
Therefore, the probability that all four have type B+ blood is 0.000041.
(b) We have to find the probability that none have B+ blood.
Using the complementary law of probability we have:
Probability that blood type is not B+ = 1 - 0.08
= 0.92
Therefore, the probability that none have B+ blood = 0.92 x 0.92 x 0.92 x 0.92
=0.716393
Therefore, the probability that none have B+ blood is 0.716393
(c) We have to find the probability that at least one of the four have B+ blood.
The probability that at least one of the four have B+ blood = 1 - Probability that none have B+ blood type
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Probability
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