Question
Asked Oct 29, 2019

The product of two consecutive integers is 19 more than their sum. Find the integers

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Expert Answer

Step 1

Let x be an integer and x+1 be its consecutive integer.

It is given that their product is...

x(x+1)x +(x +1)+ 19
х +x%3D 2х + 20
х — х— 20 %3 0
x(x-5)+4(x-5)0
(x-5)(x+ 4) 0
x 5,-4
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x(x+1)x +(x +1)+ 19 х +x%3D 2х + 20 х — х— 20 %3 0 x(x-5)+4(x-5)0 (x-5)(x+ 4) 0 x 5,-4

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Tagged in

Math

Algebra