The quantity of heat Q that changes the temperature deltaT of a mass m of a substance is given by Q=cmdeltaT, where c is the specific heat capacity of the substance. For example, for H2O, c=1cal/g degree C. And for a change of phase, the quantity of heat Q that changes the phase of a mass m is Q-mL, where L is the heat of fusion or heat of vaporization of the substance. For example, for H2O, the heat of fusion is 80 cal/ g and the heat vaporization is 540 cal/g.Part A: Use these relationships to determine the number of calories to change 0.60 kg of 100 degree C oiling water to 0.60 kg of 100 degree C steam. Express your answer to two significant figures and include appropriate units. Part B: Use these relationships to determine the number of calories to change 0.60 kg of 0 degree C ice to 0.60 kg of 100 degree C steam. Express your answer to two significant figures and include appropriate units.

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Asked Apr 18, 2019
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The quantity of heat Q that changes the temperature deltaT of a mass m of a substance is given by Q=cmdeltaT, where c is the specific heat capacity of the substance. For example, for H2O, c=1cal/g degree C. And for a change of phase, the quantity of heat Q that changes the phase of a mass m is Q-mL, where L is the heat of fusion or heat of vaporization of the substance. For example, for H2O, the heat of fusion is 80 cal/ g and the heat vaporization is 540 cal/g.

Part A: Use these relationships to determine the number of calories to change 0.60 kg of 100 degree C oiling water to 0.60 kg of 100 degree C steam. Express your answer to two significant figures and include appropriate units. 

Part B: Use these relationships to determine the number of calories to change 0.60 kg of 0 degree C ice to 0.60 kg of 100 degree C steam. Express your answer to two significant figures and include appropriate units. 

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Expert Answer

Step 1

Part A:

The question is to determine the amount of heat required to convert 0.6 kg of boiling water to 0.6 kg of steam at 1000C

Mass m = 0.6 kg = 600 grams

Given Latent heat of Vaporization of water = 540 Cal/gram

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Step 2

The question is to determine the amount heat required to heat 0.6kg (600 ...

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