Question
Asked Sep 26, 2019

The question asks for the exact value of the trigonometric function at the given real number:

 

sec(5pi/4)  I answered 2/(-(sqrt)2), but I would like to double check this answer...

check_circleExpert Solution
Step 1

Given,

...
(5п
sec
4
п
- sec (n
Since, in 3rd quadrant sec0 is negative
-sec
=
=-V2
2
Since, -2 2x
|
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(5п sec 4 п - sec (n Since, in 3rd quadrant sec0 is negative -sec = =-V2 2 Since, -2 2x |

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