Question
Asked Oct 21, 2019

The question was: Find the horizontal intercepts of the quadratic f(x)=2x2+4x-4. I utilized the quadratic formula to arrive at my answer. 

I got (-1+sqrt(3),0) and (-1-sqrt(3),0). 

I would just like to see if this is correct. 

check_circleExpert Solution
Step 1

Given,

            f(x)= 2x2 + 4x – 4

Step 2

For horizontal interce...

2x2 4x 4 = 0
Now solving for x by quadratic formula, we get
-4+/42-4(2)(-4)
x
2(2)
-4+48
x =
4
-4+4 3
x
4
> x= -1 t 3
V3, > x = -1 - V3
x 1
help_outline

Image Transcriptionclose

2x2 4x 4 = 0 Now solving for x by quadratic formula, we get -4+/42-4(2)(-4) x 2(2) -4+48 x = 4 -4+4 3 x 4 > x= -1 t 3 V3, > x = -1 - V3 x 1

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour*

See Solution
*Response times may vary by subject and question
Tagged in

Math

Algebra

Equations and In-equations

Related Algebra Q&A

Find answers to questions asked by student like you

Show more Q&A add