The reduction of iron(III) oxide (Fe,O,) to pure iron during the first step of steelmaking,2 Fe2O3(s)4Fe(s) + 30,(8)is driven by the high-temperature combustion of coke, a purified form of coal:C(s) + 02(g)-CO(g)Suppose at the temperature of a blast furnace the Gibbs free energies of formation AG, of CO, and Fe,02 are 438. kJ/mol and -838. kJ/mol, respectivelyCalculate the minimum mass of coke needed to produce 9500. kg of pure iron.Round your answer to 2 significant digits.kg?XExplanationCheckO 2019 McGraw Hill Education. All Rights ReservedTerms of Use f Prm

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Asked Nov 12, 2019
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Calculate the minimum of a mass of coke needed to produce 9500 kg of pure iron. Two sig figs for answer and don't round during the math. 

The reduction of iron(III) oxide (Fe,O,) to pure iron during the first step of steelmaking,
2 Fe2O3(s)4Fe(s) + 30,(8)
is driven by the high-temperature combustion of coke, a purified form of coal:
C(s) + 02(g)-
CO(g)
Suppose at the temperature of a blast furnace the Gibbs free energies of formation AG, of CO, and Fe,02 are 438. kJ/mol and -838. kJ/mol, respectively
Calculate the minimum mass of coke needed to produce 9500. kg of pure iron.
Round your answer to 2 significant digits.
kg
?
X
Explanation
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O 2019 McGraw Hill Education. All Rights Reserved
Terms of Use f Prm
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The reduction of iron(III) oxide (Fe,O,) to pure iron during the first step of steelmaking, 2 Fe2O3(s)4Fe(s) + 30,(8) is driven by the high-temperature combustion of coke, a purified form of coal: C(s) + 02(g)- CO(g) Suppose at the temperature of a blast furnace the Gibbs free energies of formation AG, of CO, and Fe,02 are 438. kJ/mol and -838. kJ/mol, respectively Calculate the minimum mass of coke needed to produce 9500. kg of pure iron. Round your answer to 2 significant digits. kg ? X Explanation Check O 2019 McGraw Hill Education. All Rights Reserved Terms of Use f Prm

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Expert Answer

Step 1

Calculate the energy required for the...

For the formation of Fe O
2 Fe O
>Fe.O3
AG = -838KJ/mol
for the reverseprocess
2 Fe O, AG = +838KJ/mol
Fe O
>4 Fe +302
2x(+838 kJ/mol)
2 Fe Os
For the formation of (4x56x103kg)of Feenergy needs-2x(+838KJ/mol
AG
838x2x9500
= 7.1 1x107 kJ
For the formation of 9500 kg of Fe energyneeds
4x56x10
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For the formation of Fe O 2 Fe O >Fe.O3 AG = -838KJ/mol for the reverseprocess 2 Fe O, AG = +838KJ/mol Fe O >4 Fe +302 2x(+838 kJ/mol) 2 Fe Os For the formation of (4x56x103kg)of Feenergy needs-2x(+838KJ/mol AG 838x2x9500 = 7.1 1x107 kJ For the formation of 9500 kg of Fe energyneeds 4x56x10

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