The Sin^-1(.9090) does not equal to 65 degrees. It equals 1.14. I would like to know how you got the sine of angle B TEXAS INSTRUMENTS TI-83 Plus7895037397sin-K.91)1.143284062sin1(,9090)1.140878495sin1(0.9090)1.140878495STAT PLOTF1TBLSETF2FOR MAT F3CALCF4TABLEF5Y=WINDOWZOOMTRACEGRAPHQUITINS2ndMODEDELA-LOCKLINKLISTALPHAX,T,0,nSTATTESTA ANGLEB DRAW C DISTR 9:38AB =c = 12 ; AC =b; BC= a = 5Applying pythagorous theorem in the given rightangle triangle(Hypotenuse)? = (Base)? + (Perpendicular)²c2 = a² + b²122 = 52 + b²b2 = 144 -25 = 119then b = V119Step2b)According to the given figuresinB = Perpendicular / Hypotenuse= b/c119 / 12So,sinB = V119 / 12= 10.90/12 = 0.9090B= sin(0.9090) = 65.36°Answer

Given: B=sin-10.9090 To find the angle B.

Answered: The Sin^-1(.9090) does not equal to 65…

Math

Trigonometry

The Sin^-1(.9090) does not equal to 65 degrees. It equals 1.14. I would like to know how you got the sine of angle B

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.2: Arithmetic Sequences

Problem 52E

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