# The solubility of He in water at 25 °C is 7.0 × 10⁻⁵ M when the partial pressure of He is 0.20 atm. What is the value of the Henry's law constant for He?

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The solubility of He in water at 25 °C is 7.0 × 10⁻⁵ M when the partial pressure of He is 0.20 atm. What is the value of the Henry's law constant for He?

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Step 1

The solubility of He in water at 25°C is 7.0×10-5 M when the partial pressure of He is 0.20 atm. The value of the Henry's law constant for He is to be determined.

Step 2

Henry’s law states that at a particular temperature, the amount of gas dissolving in the given liquid is directly proportional to the partial pressure of that gas over the liquid.

The amount of gas that dissolves in the liquid at a temperature can also be referred as the solubility of that gas in the given liquid.

Step 3

Calculate the value of the Henry's law constant for He-

Given –

Solubility of He in water at 25 °C = 7.0 × 10⁻⁵ M

Partial pressure of He = 0.20 atm

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