The sum of the series 1 +++…is 22

Q: Find the sum of the series if possible: 2k 1 k 1 3k 2

A:

Q: Find the sum of the series: n=0 (-1)"64"-2 n!

A: The given series is                                     ∑n=0∞-1n64n-2n! We know that    ex=∑n=0∞xnn!

Q: 10 n(n +2) n=1

A: We have to find the sum

Q: The sum of the series is k2 + 11k + 30 k=1 8.

A:

Q: Find the Sum of the series 2/3 , 4/9, 8/27 .......to infinity

A:

Q: The sum of the series 3 (-k+1) is -k k-3

A:

Q: Find the sum of the series n-1 1 n(n+2)

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Q: Vhat is the sum of the series En=0 А. 2 В. -2 N/3 C.

A:

Q: The sum of the series (-k+1) is -- k-2 8. 3 O 4 4 6. O None. 21

A:

Q: Find the sum of 10th term of the series (1) + (5+5) + (5 +5 +5°) + (5 + 5° + 5 + 5° +5°) +..

A:

Q: Find the sum of the series: n=0 (-1) 16-2 (2n)!

A: Find the sum of the series (-1)n16n-2/(2n)! from n=0 to infinity.

Q: Find the sum of the series Σ 3n(x-3)n/(n+3)! from n=1 to infinity

A: To compute: ∑n=1∞3nx-3nn+3! ∑n=1∞3nx-3nn+3!=∑n=1∞3x-9nn+3!∑n=1∞3x-9nn+3!=∑n=1∞3x-9n+33x-93n+3!Shift…

Q: Find the sum of the series: ∑∞n=0((5/2^n)−(1/3^n))=

A: The given series is

Q: The series from n=5 to infinity of 5^n/6^n, find the sum of the series?

A: As we know that the sum of infinite G.P is given by, S∞=a+ar+ar2+...+∞=a1-r Where a is the first…

Q: Find the sum of the series: S=∑∞n=0 ((−1)^n)/(4^n)=

A: According to the given information it is required to calculate the sum of the given series:

Q: Find the sum of the series: S=∑∞n=2 1/(4^n)=

A: Given, series

Q: Find the sum of the series: 2 (n + 7)(n + 5) n=1

A:

Q: Find 21st term of series 13,16,19

A: Given problem:- Find 21st term of series 13,16,19

Q: 1. What's an infinite series that can "sum" to 1?

A:

Q: Find the sum of the telescoping series k=1

A: Given telescopic series:

Q: Find the Sum of the series 1, 2/3, 4/9 , 8/27....to infinity

A: The given question is geometric sequence since there is common ratio between terms. The general…

Q: The sum of the series is 4k2-1 k=2

A:

Q: 1 Σ ak-1 k(k+ 1)(k + 2)

A: Given: ∑k=1∞1k(k+1)(k+2)

Q: The sum of the series Σ 1 is: 2" n=1

A: Given that: ∑n=1∞12n

Q: Find the sum of the series.

A: The series starts from the term n = 4 , since all the terms of the series are positive.

Q: Find the sum of the series: ∞ Σ      3(n+3) n=3

A:

Q: Find the sum of the series: n=0 1-2 (-1)" (1) " 2n + 1

A:

Q: Find the sums of the series

A: Given that ∑n=1∞(-1)n34n We need to find the sum of the series. By looking at the series it seems to…

Q: Example 4. How many terms of the series 1, 6, 11, sum is 148, be taken so that their

A:

Q: If the first term and nth term of a series are -3 and 10+2an-1  Then find second third and fourth…

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Q: п+2 п(п + 1)2"+1 n=1

A: Consider the series ∑n=1∞n+2nn+12n+1  First we will express the given series in the form of…

Q: Find the sum of the series from n=2 to ♾ of.  6/(n^2+4n+3)

A: The given series is: ∑n=2∞ 6n2+4n+3

Q: Find the sum of the series S. 3 - 3 In(3) + 3 (In(3))² - 3 (In(3))² ... 2! 3! S =|| !!

A: Sum of series

Q: Find the Sum of the series (눈 k²+3K

A:

Q: is The sum of the series > 4k²–1 k=5 8.

A:

Q: Suppose that an = 5 and b, =1 and a =7 and b, = -9, find the sum of the series: n=1 n=1 A. (-5a, +…

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Q: Calculate the sum of the series 7 + ++ +

A: We need to evaluate the following sum 7+52+54+58+516+532+······

Q: Find the exact sum of the series 1 - 1 + (1/2!) - (1/3!) + (1/4!) - (1/5!) + (1/6!) - ...

A: Topic:- sequence and series

Q: Find the sum of the series Σ 1/n(n+2) from n=1 to infinity

A: Given : ∑n=1∞1nn+2

Q: Find the sum of the series below. 1 Σ In (n + 4) In (n +3). n= 1

A:

Q: Find the sum of the series.

A: The series is:

Q: . Therefore the series >

A:

Q: Determine whether the series Σ is k+4

A: we have to determine whether the given series is convergent or divergent using Kth - term…

Q: Find the sum of the series: n=0 2-1 (-1)"64"- n!

A:

Q: Find the sum of the series Σ[1/n - 1/(n+1)]  from n=8 to infinity

A: Consider the following expression:…

Q: -2 2 ntl nt2 n=2

A: Given

Q: Find the sum of the series Σ /n+4 n = 1

A: First operate the given sum on both terms and then calculate the sum.