# The USA Today reports that the average expenditure on Valentine's Day is \$100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 41 maleconsumers was \$135.67. and the average expenditure in a sample survey of 40 female consumers was \$68.64. Based on past surveys, the standard deviation for male consumers is assumed to be \$37, andExercise 10.27 Algorithmic: Not Answeredtne tmuuru uCnutionnvnmnurC coNsumers IS assumed to be \$21.a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)?b. At 99% confidence, what is the margin of error (to 2 decimals)?c. Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table.

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68 views help_outlineImage TranscriptioncloseThe USA Today reports that the average expenditure on Valentine's Day is \$100.89. Do male and female consumers differ in the amounts they spend? The average expenditure in a sample survey of 41 male consumers was \$135.67. and the average expenditure in a sample survey of 40 female consumers was \$68.64. Based on past surveys, the standard deviation for male consumers is assumed to be \$37, and Exercise 10.27 Algorithmic: Not Answered tne tmuuru uCnutionnvnmnurC coNsumers IS assumed to be \$21. a. What is the point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females (to 2 decimals)? b. At 99% confidence, what is the margin of error (to 2 decimals)? c. Develop a 99% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. fullscreen
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Step 1

The provided information are: help_outlineImage TranscriptioncloseFor male n 41 X 135.67 a37 For female n2 40 X 68.64 a221 fullscreen
Step 2

(a)

The point estimate of the difference between the population mean expenditure for males and the population mean expenditure for females can be calculated as:

Step 3

(b)

The margin of error can ... help_outlineImage TranscriptioncloseThe value of za corresponding to 99% confidence level is 2.575, which is obtained from the standard normal table. σ' Margin of error = zx п п, 372 212 =2.575x, 41 40 =17.16 fullscreen

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