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PhysicsQ&A LibraryThe vector position of a 3.85 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.40 g particle varies as r2 = 3î − 2ît2 − 6ĵt.(a)Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s.rcm = cm(b)Determine the linear momentum (in g · cm/s) of the system at t = 2.80 s.p = g · cm/s(c)Determine the velocity (in cm/s) of the center of mass at t = 2.80 s.vcm = cm/s(d)Determine the acceleration (in cm/s2) of the center of mass at t = 2.80 s.acm = cm/s2(e)Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s.Fnet = µNQuestion

Asked Dec 6, 2019

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The vector position of a 3.85 g particle moving in the *xy* plane varies in time according to r_{1} = (3î + 3ĵ)t + 2ĵt^{2 }where *t* is in seconds and r is in centimeters. At the same time, the vector position of a 5.40 g particle varies as r_{2} = 3î − 2ît^{2} − 6ĵt.

(a)

Determine the vector position (in cm) of the center of mass of the system at *t* = 2.80 s.

r_{cm} = cm

(b)

Determine the linear momentum (in g · cm/s) of the system at *t* = 2.80 s.

p = g · cm/s

(c)

Determine the velocity (in cm/s) of the center of mass at *t* = 2.80 s.

v_{cm} = cm/s

(d)

Determine the acceleration (in cm/s^{2}) of the center of mass at *t* = 2.80 s.

a_{cm} = cm/s^{2}

(e)

Determine the net force (in µN) exerted on the two-particle system at *t* = 2.80 s.

F_{net} = µN

Step 1

Mass of the first particle (m_{1}),

Step 2

Position, velocity and acceleration vector of the first particles,

Step 3

Mass of the second particl...

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