The velocity v, in feet per second, of the water pouring out of a small hole in the bottom of a cylindrical tank is given byv =  64h + 10,where h is the height, in feet, of the water in the tank. What is the height of the water in the tank when the velocity of the water leaving the tank is 17 ft/s? Round to the nearest tenth.ft

Question
Asked Nov 16, 2019
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The velocity v, in feet per second, of the water pouring out of a small hole in the bottom of a cylindrical tank is given by

v = 
  64h + 10
,

where h is the height, in feet, of the water in the tank. What is the height of the water in the tank when the velocity of the water leaving the tank is 17 ft/s? Round to the nearest tenth.
ft

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Expert Answer

Step 1

The velocity v, in feet per second, of the water pouring out of a small hole in the bottom of a cylindrical tank is given by

v 64h10
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v 64h10

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Step 2

To find the height of the water in the tank when the velocity of the water leavin...

v 17
64h 10 17
64h 7
7
= 0.1ft
h =
64
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Image Transcriptionclose

v 17 64h 10 17 64h 7 7 = 0.1ft h = 64

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Algebra

Equations and In-equations