Asked Dec 9, 2019

The wavefunction of is Ψ(x) = Axe(−ax^2)/2 
for with energy E = 3aℏ2/2m. 
Find the bounding potential V(x). Looking at the potential’s form, can you write down the two energy levels that are immediately above E?


Expert Answer

Step 1

Given wave function of is Ψ(x) = Axe (−ax^2)/2 

Step 2

To determine the normali...


Image Transcriptionclose

Y (x) = Axe*y2 ¥(x) = [|Y(x)* äx dx = 4[xe-z)/2 2! 2.4 f|Y(x)/ dx = 1 hence 2.4 ||


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