The x-coordinate of a particle in curvilinear motion is given by x = 2.0t3 - 3.0t where x is in feet and t is in seconds. The y- component of acceleration in feet per second squared is given by ay = 4.0t. If the particle has y-components y = 0 and vy 4.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.0 sec. Sketch the path for the first 2.0 seconds of motion, and show the velocity and acceleration vectors for t = 2.0 sec. Answers: V= a= i i ft/sec ft/sec² 2.

The x-coordinate of a particle in curvilinear motion is given by x = 2.0t3 - 3.0t where x is in feet and t is in seconds. The y- component of acceleration in feet per second squared is given by ay = 4.0t. If the particle has y-components y = 0 and vy 4.0 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t = 2.0 sec. Sketch the path for the first 2.0 seconds of motion, and show the velocity and acceleration vectors for t = 2.0 sec. Answers: V= a= i i ft/sec ft/sec² 2.

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter8: Time And Time-related Variables In Engineering

Section: Chapter Questions

Problem 29P

See similar textbooks

Similar questions

2. A particle moves along a straight line with the equation x=16t+4t2-3t3 where x is the distance in ft and t is the time in second. Compute the acceleration of the particle after 2 seconds?
The motion of a particle is defined by the parametric equations ax =0.8t, ay =2–0.3t, az =5 where “a” is in m/s2 and t in seconds.The particle is at rest and is placed at the origin at t = 0. What is the acceleration of the particle after 10 seconds? What is the velocity of the particle after 10 seconds?
Situation 2: The displacement (in meter) of a particle moving along x - axis is givenby x=At^2 + B , where A = 2m and B = 3m. Calculate average velocity between t =3sand t = 5s.Situation 2: Calculate instantaneous velocity at t = 5sSituation 2: Calculate instantaneous acceleration.
1.The location of a certain particle that is only limited to move along a linear direction is given by S = 2t^3 – 24t + 6, such that the unit of s is in meters from an acceptable origin and t is measured in seconds. Solve for the following: -The time needed for that certain particle to attain a velocity of 72 m/s from rest when t = 0. -The acceleration of the particle when it reaches V = 30 m/s -Net displacement in meters from t = 1 second to t = 4 seconds
Find how far an airplane will move in landing, if in t seconds after touching the ground its speed in feet per second is given by the equation. v= 180 – 18t. (hint: take v=0, C=0 ).
The acceleration of a particle moving along the x-axis at time t is given by a(t) = 4t - 12. If the velocity is 10 when t=0 and the positive is 4 when t=0, then the particle is changing direction at t=?
A plane motion of a particle is described in polar coordinates as R = 0.75 + 0.5t2 (m) and θ=πt2/2 (rad), where t is measured in seconds. Find the magnitudes of the acceleration when t =2.83s.
Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. The rotation of the 0.9-m arm OA about O is defined by the relation Eq. (1), where θ is expressed in radians and t in seconds. Collar B slides along the arm in such a way that its distance from O is Eq. (2), where r is expressed in meters and t in seconds. After the arm OA has rotated through 30°, determine the relative acceleration of the collar with respect to the arm (m/s^2).
! Use the Given Data in Solving ! Rectilinear Motion: A particle travels in v = (12 - 3t^2) m/s, where t is in seconds. When t = 1 s, the particle is located 32.8 ft to the left of the origin. Determine the displacement (m) from t = 0 t = 10 s, and the distance (m) the particle travels during this time period.
The topic is all about the Angular Motion of Particles. Please use pen and paper to solve and also use three decimal places. Please show the conversion solution. Thank you. Here are the formulas: θ=θ_o+ω_o t+1/2 αt^2 ω=ω_0+αt ω^2=ω_o^2+2α(θ-θ_o) considering the tangential and normal components of the acceleration in a curvilinear motion of particles: a_t=rα a_n=rω^2=vω The angular motion may be derived from the translational motion of particles by considering the given circle: s=rθ ds/dt=r dθ/dt or v=rω dv/dt=r dω/dt or a=rα
A particle travels counterclockwise around a circle of 36m radius so that the distance from a fixed point 0 on the right end of a horizontal diameter is given by s=20t + 2t^2 where s is in meters and t is in seconds. Compute the rectangular components of acceleration at the end of 2 seconds.
Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. The rotation of the 0.9-m arm OA about O is defined by the relation Eq. (1), where θ is expressed in radians and t in seconds. Collar B slides along the arm in such a way that its distance from O is Eq. (2), where r is expressed in meters and t in seconds. After the arm OA has rotated through 30°, determine the acceleration of the collar (m/s^2).