THEOREM 4.9 One Local Extremum Implies Absolute Extremum Suppose f is continuous on an interval I that contains exactly one local extremum at c. • If a local maximum occurs at c, then f(c) is the absolute maximum of f on I. • If a local minimum occurs at c, then f(c) is the absolute minimum of f on I.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 99E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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Verify that the following function satisfy the conditions of Theorem on their domains. Then find the location and value of the absolute extrema guaranteed by the theorem.

ƒ(x) = 4x + 1/√x

THEOREM 4.9 One Local Extremum Implies Absolute Extremum
Suppose f is continuous on an interval I that contains exactly one local extremum at c.
• If a local maximum occurs at c, then f(c) is the absolute maximum of f on I.
• If a local minimum occurs at c, then f(c) is the absolute minimum of f on I.
Transcribed Image Text:THEOREM 4.9 One Local Extremum Implies Absolute Extremum Suppose f is continuous on an interval I that contains exactly one local extremum at c. • If a local maximum occurs at c, then f(c) is the absolute maximum of f on I. • If a local minimum occurs at c, then f(c) is the absolute minimum of f on I.
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