There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC2(s) + 2 H2O(g) → C„H,(9) + Ca(OH)2(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C,H2(9) + 3 CO2(9) + 4 H2O(9) → 5 CH,CHCO,H(9) AH=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ.

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.20P: 4-20 Calcium oxide is prepared by heating limestone (calcium carbonate, CaCO3) to a high...
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and
water react to form acetylene and calcium hydroxide:
CaC,(s) + 2 H,0(g) → C,H,(9) + Ca(OH),(s)
AH=-414. kJ
In the second step, acetylene, carbon dioxide and water react to form acrylic acid:
6C,H2(g) + 3 C0,(g) + 4 H,O(g) → 5 CH,CHCO,H(g)
AH=132. kJ
Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions.
Round your answer to the nearest kJ.
O kJ
Transcribed Image Text:There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC,(s) + 2 H,0(g) → C,H,(9) + Ca(OH),(s) AH=-414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C,H2(g) + 3 C0,(g) + 4 H,O(g) → 5 CH,CHCO,H(g) AH=132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. O kJ
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