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There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 11.4 cm. When the cylinder is rotating at 1.36 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

Question

There is a clever kitchen gadget for drying lettuce leaves after you wash them. It consists of a cylindrical container mounted so that it can be rotated about its axis by turning a hand crank. The outer wall of the cylinder is perforated with small holes. You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 11.4 cm. When the cylinder is rotating at 1.36 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

check_circleAnswer
Step 1

Given:

Angular velocity of the cylinder = 1.36 rev per second

Radius of the cylinder, R = 11.4 cm = 0.114 m

Step 2

Calculating the centripital acceleration ...

Angular velocity of the cylinder = 1.36 rev per second
1 revolution 2T radians
Hence, angular velocity,
2nrad
rev
1.36x
rev
8.54rad/s
Centripital acceleration, a.ri = R
Substuting values,
aentripital = (8.54)(0.114) = 8.31m /s2
aentripital = 8.31m /s2
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Angular velocity of the cylinder = 1.36 rev per second 1 revolution 2T radians Hence, angular velocity, 2nrad rev 1.36x rev 8.54rad/s Centripital acceleration, a.ri = R Substuting values, aentripital = (8.54)(0.114) = 8.31m /s2 aentripital = 8.31m /s2

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Physics

Rotational Mechanics

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