This question has 2 parts: 9.762 g of a non-volatile solute is dissolved in 175.0 g of water.The solute does not react with water nor dissociate in solution.Assume that the resulting solution displays ideal Raoult's law behaviour.At 25°C the vapour pressure of the solution is 23.405 torr.The vapour pressure of pure water at 25°C is 23.756 torr.Calculate the molar mass of the solute (g/mol). Now suppose, instead, that 9.762 g of a volatile solute is dissolved in 175.0 g of water.This solute also does not react with water nor dissociate in solution.The pure solute displays, at 25°C, a vapour pressure of 2.376 torr.Again, assume an ideal solution.If, at 25°C the vapour pressure of this solution is also 23.405 torr.Calculate the molar mass of this volatile solute.

The expression for Raoult’s law containing non-volatile solute is given below in which p○ is the…

Answered: This question has 2 parts: 9.762 g of…

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter12: Solutions

Section: Chapter Questions

Problem 12.84QE

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This question has 2 parts:

9.762 g of a non-volatile solute is dissolved in 175.0 g of water.
The solute does not react with water nor dissociate in solution.
Assume that the resulting solution displays ideal Raoult's law behaviour.
At 25°C the vapour pressure of the solution is 23.405 torr.
The vapour pressure of pure water at 25°C is 23.756 torr.
Calculate the molar mass of the solute (g/mol).

Now suppose, instead, that 9.762 g of a volatile solute is dissolved in 175.0 g of water.
This solute also does not react with water nor dissociate in solution.
The pure solute displays, at 25°C, a vapour pressure of 2.376 torr.
Again, assume an ideal solution.
If, at 25°C the vapour pressure of this solution is also 23.405 torr.
Calculate the molar mass of this volatile solute.

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